8x^2+100x-600=0

Solution for 8x^2+100x-600=0 equation:

8x^2+100x-600=0

a = 8; b = 100; c = -600;
Δ = b2-4ac
Δ = 1002-4·8·(-600)
Δ = 29200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{29200}=\sqrt{400*73}=\sqrt{400}*\sqrt{73}=20\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{73}}{2*8}=\frac{-100-20\sqrt{73}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{73}}{2*8}=\frac{-100+20\sqrt{73}}{16}
$